Optimal. Leaf size=241 \[ -\frac{p \text{PolyLog}\left (2,\frac{\sqrt{-a} (d+e x)}{\sqrt{-a} d-\sqrt{b} e}\right )}{e}-\frac{p \text{PolyLog}\left (2,\frac{\sqrt{-a} (d+e x)}{\sqrt{-a} d+\sqrt{b} e}\right )}{e}+\frac{2 p \text{PolyLog}\left (2,\frac{e x}{d}+1\right )}{e}+\frac{\log (d+e x) \log \left (c \left (a+\frac{b}{x^2}\right )^p\right )}{e}-\frac{p \log (d+e x) \log \left (\frac{e \left (\sqrt{b}-\sqrt{-a} x\right )}{\sqrt{-a} d+\sqrt{b} e}\right )}{e}-\frac{p \log (d+e x) \log \left (-\frac{e \left (\sqrt{-a} x+\sqrt{b}\right )}{\sqrt{-a} d-\sqrt{b} e}\right )}{e}+\frac{2 p \log \left (-\frac{e x}{d}\right ) \log (d+e x)}{e} \]
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Rubi [A] time = 0.334294, antiderivative size = 241, normalized size of antiderivative = 1., number of steps used = 13, number of rules used = 7, integrand size = 20, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.35, Rules used = {2462, 260, 2416, 2394, 2315, 2393, 2391} \[ -\frac{p \text{PolyLog}\left (2,\frac{\sqrt{-a} (d+e x)}{\sqrt{-a} d-\sqrt{b} e}\right )}{e}-\frac{p \text{PolyLog}\left (2,\frac{\sqrt{-a} (d+e x)}{\sqrt{-a} d+\sqrt{b} e}\right )}{e}+\frac{2 p \text{PolyLog}\left (2,\frac{e x}{d}+1\right )}{e}+\frac{\log (d+e x) \log \left (c \left (a+\frac{b}{x^2}\right )^p\right )}{e}-\frac{p \log (d+e x) \log \left (\frac{e \left (\sqrt{b}-\sqrt{-a} x\right )}{\sqrt{-a} d+\sqrt{b} e}\right )}{e}-\frac{p \log (d+e x) \log \left (-\frac{e \left (\sqrt{-a} x+\sqrt{b}\right )}{\sqrt{-a} d-\sqrt{b} e}\right )}{e}+\frac{2 p \log \left (-\frac{e x}{d}\right ) \log (d+e x)}{e} \]
Antiderivative was successfully verified.
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Rule 2462
Rule 260
Rule 2416
Rule 2394
Rule 2315
Rule 2393
Rule 2391
Rubi steps
\begin{align*} \int \frac{\log \left (c \left (a+\frac{b}{x^2}\right )^p\right )}{d+e x} \, dx &=\frac{\log \left (c \left (a+\frac{b}{x^2}\right )^p\right ) \log (d+e x)}{e}+\frac{(2 b p) \int \frac{\log (d+e x)}{\left (a+\frac{b}{x^2}\right ) x^3} \, dx}{e}\\ &=\frac{\log \left (c \left (a+\frac{b}{x^2}\right )^p\right ) \log (d+e x)}{e}+\frac{(2 b p) \int \left (\frac{\log (d+e x)}{b x}-\frac{a x \log (d+e x)}{b \left (b+a x^2\right )}\right ) \, dx}{e}\\ &=\frac{\log \left (c \left (a+\frac{b}{x^2}\right )^p\right ) \log (d+e x)}{e}+\frac{(2 p) \int \frac{\log (d+e x)}{x} \, dx}{e}-\frac{(2 a p) \int \frac{x \log (d+e x)}{b+a x^2} \, dx}{e}\\ &=\frac{\log \left (c \left (a+\frac{b}{x^2}\right )^p\right ) \log (d+e x)}{e}+\frac{2 p \log \left (-\frac{e x}{d}\right ) \log (d+e x)}{e}-(2 p) \int \frac{\log \left (-\frac{e x}{d}\right )}{d+e x} \, dx-\frac{(2 a p) \int \left (-\frac{\sqrt{-a} \log (d+e x)}{2 a \left (\sqrt{b}-\sqrt{-a} x\right )}+\frac{\sqrt{-a} \log (d+e x)}{2 a \left (\sqrt{b}+\sqrt{-a} x\right )}\right ) \, dx}{e}\\ &=\frac{\log \left (c \left (a+\frac{b}{x^2}\right )^p\right ) \log (d+e x)}{e}+\frac{2 p \log \left (-\frac{e x}{d}\right ) \log (d+e x)}{e}+\frac{2 p \text{Li}_2\left (1+\frac{e x}{d}\right )}{e}+\frac{\left (\sqrt{-a} p\right ) \int \frac{\log (d+e x)}{\sqrt{b}-\sqrt{-a} x} \, dx}{e}-\frac{\left (\sqrt{-a} p\right ) \int \frac{\log (d+e x)}{\sqrt{b}+\sqrt{-a} x} \, dx}{e}\\ &=\frac{\log \left (c \left (a+\frac{b}{x^2}\right )^p\right ) \log (d+e x)}{e}+\frac{2 p \log \left (-\frac{e x}{d}\right ) \log (d+e x)}{e}-\frac{p \log \left (\frac{e \left (\sqrt{b}-\sqrt{-a} x\right )}{\sqrt{-a} d+\sqrt{b} e}\right ) \log (d+e x)}{e}-\frac{p \log \left (-\frac{e \left (\sqrt{b}+\sqrt{-a} x\right )}{\sqrt{-a} d-\sqrt{b} e}\right ) \log (d+e x)}{e}+\frac{2 p \text{Li}_2\left (1+\frac{e x}{d}\right )}{e}+p \int \frac{\log \left (\frac{e \left (\sqrt{b}-\sqrt{-a} x\right )}{\sqrt{-a} d+\sqrt{b} e}\right )}{d+e x} \, dx+p \int \frac{\log \left (\frac{e \left (\sqrt{b}+\sqrt{-a} x\right )}{-\sqrt{-a} d+\sqrt{b} e}\right )}{d+e x} \, dx\\ &=\frac{\log \left (c \left (a+\frac{b}{x^2}\right )^p\right ) \log (d+e x)}{e}+\frac{2 p \log \left (-\frac{e x}{d}\right ) \log (d+e x)}{e}-\frac{p \log \left (\frac{e \left (\sqrt{b}-\sqrt{-a} x\right )}{\sqrt{-a} d+\sqrt{b} e}\right ) \log (d+e x)}{e}-\frac{p \log \left (-\frac{e \left (\sqrt{b}+\sqrt{-a} x\right )}{\sqrt{-a} d-\sqrt{b} e}\right ) \log (d+e x)}{e}+\frac{2 p \text{Li}_2\left (1+\frac{e x}{d}\right )}{e}+\frac{p \operatorname{Subst}\left (\int \frac{\log \left (1+\frac{\sqrt{-a} x}{-\sqrt{-a} d+\sqrt{b} e}\right )}{x} \, dx,x,d+e x\right )}{e}+\frac{p \operatorname{Subst}\left (\int \frac{\log \left (1-\frac{\sqrt{-a} x}{\sqrt{-a} d+\sqrt{b} e}\right )}{x} \, dx,x,d+e x\right )}{e}\\ &=\frac{\log \left (c \left (a+\frac{b}{x^2}\right )^p\right ) \log (d+e x)}{e}+\frac{2 p \log \left (-\frac{e x}{d}\right ) \log (d+e x)}{e}-\frac{p \log \left (\frac{e \left (\sqrt{b}-\sqrt{-a} x\right )}{\sqrt{-a} d+\sqrt{b} e}\right ) \log (d+e x)}{e}-\frac{p \log \left (-\frac{e \left (\sqrt{b}+\sqrt{-a} x\right )}{\sqrt{-a} d-\sqrt{b} e}\right ) \log (d+e x)}{e}-\frac{p \text{Li}_2\left (\frac{\sqrt{-a} (d+e x)}{\sqrt{-a} d-\sqrt{b} e}\right )}{e}-\frac{p \text{Li}_2\left (\frac{\sqrt{-a} (d+e x)}{\sqrt{-a} d+\sqrt{b} e}\right )}{e}+\frac{2 p \text{Li}_2\left (1+\frac{e x}{d}\right )}{e}\\ \end{align*}
Mathematica [A] time = 0.0573689, size = 242, normalized size = 1. \[ -\frac{p \text{PolyLog}\left (2,\frac{\sqrt{-a} (d+e x)}{\sqrt{-a} d-\sqrt{b} e}\right )}{e}-\frac{p \text{PolyLog}\left (2,\frac{\sqrt{-a} (d+e x)}{\sqrt{-a} d+\sqrt{b} e}\right )}{e}+\frac{2 p \text{PolyLog}\left (2,\frac{d+e x}{d}\right )}{e}+\frac{\log (d+e x) \log \left (c \left (a+\frac{b}{x^2}\right )^p\right )}{e}-\frac{p \log (d+e x) \log \left (\frac{e \left (\sqrt{b}-\sqrt{-a} x\right )}{\sqrt{-a} d+\sqrt{b} e}\right )}{e}-\frac{p \log (d+e x) \log \left (-\frac{e \left (\sqrt{-a} x+\sqrt{b}\right )}{\sqrt{-a} d-\sqrt{b} e}\right )}{e}+\frac{2 p \log \left (-\frac{e x}{d}\right ) \log (d+e x)}{e} \]
Antiderivative was successfully verified.
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Maple [F] time = 0.763, size = 0, normalized size = 0. \begin{align*} \int{\frac{1}{ex+d}\ln \left ( c \left ( a+{\frac{b}{{x}^{2}}} \right ) ^{p} \right ) }\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Maxima [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\log \left ({\left (a + \frac{b}{x^{2}}\right )}^{p} c\right )}{e x + d}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Fricas [F] time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{\log \left (c \left (\frac{a x^{2} + b}{x^{2}}\right )^{p}\right )}{e x + d}, x\right ) \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Sympy [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\log{\left (c \left (a + \frac{b}{x^{2}}\right )^{p} \right )}}{d + e x}\, dx \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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Giac [F] time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{\log \left ({\left (a + \frac{b}{x^{2}}\right )}^{p} c\right )}{e x + d}\,{d x} \end{align*}
Verification of antiderivative is not currently implemented for this CAS.
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